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Chapter 17 | Kinetics 925
given here. What is the activation energy for the reaction?
T (K)
k (L/mol/s)
555
3.52 10−7
575
1.22 10−6
645
8.59 10−5
700
1.16 10−3
781
3.95 10−2
Solution
Values of and ln k are:
ln k
1.80 10−3
−14.860
1.74 10−3
−13.617
1.55 10−3
−9.362
1.43 10−3
−6.759
1.28 10−3
−3.231
Figure 17.18 is a graph of ln k versus To determine the slope of the line, we need two values of ln k, which are determined from the line at two values of (one near each end of the line is preferable). For example, the value of ln k determined from the line when is −2.593; the value when
is −14.447.