Page 348 - Physics Coursebook 2015 (A level)
P. 348

  Substance
  c/Jkg−1K−1
  336
Cambridge International A Level Physics
WORKED EXAMPLE
  The specific heat capacity of a substance is the energy required per unit mass of the substance to raise the temperature by 1 K (or 1 °C).
 Calculating energy changes
So far, we have considered the effects of heating a substance in qualitative terms, and we have given an explanation in terms of a kinetic model of matter. Now we will look at the amount of energy needed to change the temperature of something, and to produce a change of state.
Specific heat capacity
If we heat some material so that its temperature rises, the amount of energy we must supply depends on three things:
■■ the mass m of the material we are heating
■■ the temperature change Δθ we wish to achieve
■■ the material itself.
Some materials are easier to heat than others. It takes more energy to raise the temperature of 1 kg of water by 1 °C than to raise the temperature of 1 kg of alcohol by the same amount.
We can represent this in an equation. The amount of energy E that must be supplied is given by:
E = mcΔθ
where c is the specific heat capacity of the material.
Rearranging this equation gives: c=E
aluminium 880
copper 380
lead 126
    glass
ice
water
seawater
ethanol
mercury
Table 21.3
500–680
2100
4180
3950
2500
140
      mΔθ
The specific heat capacity of a material can be defined as a word equation as follows:
mΔθ
We need to write down the quantities that we know:
specific heat capacity =
energy supplied
mass × temperature change
Step2 Nowsubstitutethesevaluesandsolvethe equation:
c=E mΔθ
c = 26400 = 880Jkg−1K−1 (2.0 × 15)
QUESTIONS
You will need to use data from Table 21.3 to answer these questions.
7 Calculate the energy which must be supplied to raise the temperature of 5.0 kg of water from 20 °C to100°C.
8 Which requires more energy, heating a 2.0 kg block of lead by 30 K, or heating a 4.0 kg block of copper by 5.0 K?
9 A well-insulated 1.2 kg block of iron is heated using a 50 W heater for 4.0 min. The temperature of the block rises from 22 °C to 45 °C. Find the experimental value for the specific heat capacity of iron.
Values of specific heat capacity.
 1 When 26 400 J of energy is supplied to a 2.0 kg block of aluminium, its temperature rises from 20 °C to 35 °C. The block is well insulated so that there is
no energy loss to the surroundings. Determine the specific heat capacity of aluminium.
Step1 Wearegoingtousetheequation: c=E
E = 26400J m = 2.0kg Δθ = (35−20)°C = 15°C
(or 15K)
 Alternatively, specific heat capacity can be defined in words as follows:
The word ‘specific’ here means ‘per unit mass’, i.e. per kg. From this form of the equation, you should be able to see that the units of c are J kg−1 K−1 (or J kg−1 °C−1). Table 21.3 shows some values of specific heat capacity measured at 0 °C.
Specific heat capacity is related to the gradient of the sloping sections of the graph shown earlier in Figure 21.4. The steeper the gradient, the faster the substance heats
up, and hence the lower its specific heat capacity must be. Worked example 1 shows how to calculate the specific heat capacity of a substance.
   







































   346   347   348   349   350