Page 503 - Introduction to Programming with Java: A Problem Solving Approach

Review Question Solutions
1. byte􏰂8bits,short􏰂16bits,int􏰂32bits,long􏰂64bits
2. 1.602E-19 or 1.602e-19
3. float precision 􏰏 6 digits, double precision 􏰏 15 digits
4. The basic ASCII character set describes 128 different characters.
5. To convert uppercase to lowercase, add 32. To go the other way, subtract 32.
6. System.out.println((long) C); // (int) isn’t big enough!
7. This statement is OK:
float price = 66;
8. This statement generates a compile-time error because it’s illegal to convert between numeric values and boolean values:
boolean done = (boolean) 0;
9. This statement generates a compile-time error because floating point constants are double by default: float price = 98.1;
10. z’s value is 4. The first decrement uses prefix mode so x is first decremented to 2, then 2 is assigned into z. The second decrement uses postfix mode so x is decremented after its value of 2 is added to z.
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11. w = x = y = z;oranyothersequencethathaszontheright.
12. The switch controlling expression evaluates to 'M'
13. Expression-evaluation practice:
a) a + ( 2 2 + 2 + 4.5
b) 7 + 7 + 7 + 7 + 7 +
12
c) a * 2 * 2 *
25 / (x + 2)⇒
+ 25 / (8.0 + 2) ⇒ 25 / 10.0 ⇒
2.5 ⇒
a * --b / 2⇒ 2 * --6 / 2⇒ 2 * 5 / 2⇒
10 / 2 ⇒
5⇒
--b / 6 ⇒ --6 / 6 ⇒
5 / 6⇒
Review Question Solutions 469
d)
a
+ b++ ⇒
+ 6 (b is updated to 7 after its value is accessed) ⇒
10 / 6 ⇒ 1
2
8