Page 32 - Algebra
P. 32
6. The product of slope of two perpendicular lines is –1 m1m2 =–1
Slope of line passing through
m1 = m2 =
m1m2 =–1 –1
12 = 9 – b b = –3
(x1, y1) and (x2, y2) = 𝑦2− 𝑦1 𝑥2− 𝑥1
−4−8 −12 9−𝑏 = 9−𝑏
−7−4 −11
==1
−5−6 −11
−12 ×1 9−𝑏
=
Page 31 of 177
Algebra I & II
