Page 50 - Arithmetic

Answer:
1. e 2. a 3. d 4. c 5. e 6. d 7. c
Explanation:
1. Part of the tank filled by the three pipes in 4 minutes = 4 ( 1
40 24 20 15
Part of the chemical filled by R in 4 minutes = 4 = 1 24 6
Proportion of chemical V in the tank in 4 minutes = 1 × 15 = 5 6 7 14
2. Part filled in 4 minutes = 4 ( 1 + 1 ) = 3 24 30 10
Remaining part to be filled = 1 - =
Part filled by M in one minute = 1 30
1 : 7 :: 1: x 30 10
x = 30 × 7 × 1 = 21 minutes 10
Remaining part will be filled by M in 21 minutes
1112
3. Partfilledin10hours=10( + − )=
Remaining part to be filled = 1 - =
U and V one-hour work = 4 : 13 :: 1: x
x = 75× 13 × 1 = 65 hours 415 4
15 15 1 + 1 = 4
30 50 75
75 15
37
10 10
30 50 25 15
2 13
Remaining part will be filled in 65 hours 4
4. Let us assume that the trains meet x hours after 12 noon.
Distance moved by one train in x hours + Distance moved by the other in (x-1) hours = 265 40x + 35(x-1) = 265
75x – 35 = 265
75x = 300
x = 4 hours
Therefore, the trains will meet at 4 p.m
+ 1 +
1 ) = 7
Page 49 of 55
Arithmetic Concept