Page 1651 - College Physics For AP Courses

Answer Key 1639
Test Prep for AP® Courses
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(a), (b)
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(b)
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(a) 4-Ω resistor; (b) combination of 20-Ω, 20-Ω, and 10-Ω resistors; (c) 20 W in each 20-Ω resistor, 40 W in 10-Ω resistor, 64 W in 4-Ω resistor, total 144W total in resistors, output power is 144 W, yes they are equal (law of conservation of energy); (d) 4 Ω and 3 Ω for part (a) and no change for part (b); (e) no effect, it will remain the same. 7
0.25 Ω, 0.50 Ω, no change
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a. (c) b. (c) c. (d) d. (d) 11
a. I1+I3=I2
b. E1 - I1R1 - I2R2 - I1r1 = 0; - E2 + I1R1 - I3R3 - I3r2 = 0
c. I1 = 8/15 A, I2 = 7/15 A and I3 = -1/15 A
d. I1 = 2/5 A, I2 = 3/5 A and I3 = 1/5 A
e. PE1 = 18/5 W and PR1 = 24/25 W, PR2 = 54/25 W, PR3 = 12/25 W. Yes, PE1 = PR1+ PR2 + PR3
f. R3, losses in the circuit
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(a) 20 mA, Figure 21.44, 5.5 s; (b) 24 mA, Figure 21.35, 2 s Chapter 22
Problems & Exercises
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(a) Left (West) (b) Into the page (c) Up (North) (d) No force
(e) Right (East) (f) Down (South) 3
(a) East (right) (b) Into page
(c) South (down) 5
(a) Into page
(b) West (left) (c) Out of page 7
perpendicular to both the magnetic field lines and the velocity 9
(a)
(b) This is slightly less then the magnetic field strength of at the surface of the Earth, so it is consistent.