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1664 Answer Key
(b) 54.4 eV
23
so that From the equation we can substitute for the
velocity, giving: so that where
25
(a) (b) 50.0 keV
.
(c) The photon energy is simply the applied voltage times the electron charge, so the value of the voltage in volts is the same as the value of the energy in electron volts.
27
(a)
(b)
29
(a) (b) 30 (a) (b)
,
8.00 keV 9.48 keV
1.96 eV
(c) 60.0 nm
32
693 nm
34
(a) 590 nm
(b)
35
are possible since and . 37
are possible. 39
(a)
(b)
41
(a)
(b)
(c)
43
44
(a) 32. (b) and 14 in , for a total of 32. 46
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