Page 33 - Algebra 1
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10. It’s given that f(x) = g(x) x + 5 = 5x2 – 1
5x2 – 1 – x – 5 = 0
5x2 –x–6=0
5x2 +5x–6x–6=0 5x( x + 1) – 1( x + 1) = 0 (5x – 1) (x + 1) = 0
x=–1or 1 5
11. f(x) = 𝑥 |𝑥|
The function is defined as f(x) = 𝑥, 𝑥≥0
–x, x<0 For 𝑥 ≥ 0,
f(x)=𝑥 =1 𝑥
For x < 0
f(x) = 𝑥 = –1
f(x) gives the output as 1 and –1. So, range = {1, –1}
−𝑥
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ALGEBRA
