Page 38 - Algebra 1
P. 38
Explanation:
1. Here,
p1 =3,p2 =6,q1=k,q2 =β5,r1=7,r2 =β3 The two equations has no solution when
π1 = π1 =ΜΈ π1, then the pair of linear equation has no solution. π2 π2 π2
3=π=ΜΈ7 6 β5 β3
3=π 6 β5
1=π 2 β5
β5 k=2
2. Let the cost of one table be x Let the cost of one chair be y 4x + 3y = 800.............(1)
8x + 5y = 1500...........(2) Multiply (1) by 2
8x + 6y = 1600........... (3) (3) β (2)
y = 100
4x + 3(100) = 800
4x = 500
x = 125
Cost of 3 tables and 3 chairs = 3x + 3y = 3(125) + 3(100) = 375 + 300 = $675
3.
Let the numerator of the fraction is x
The denominator of the fraction be y
π₯+2 = 1
π¦β3 3
3(x + 2) = (y β 3)
3x + 6 = y β 3
3x β y + 9 = 0......................(1)
π₯β3 = 1
π¦+1 4
4(x β 3) = (y + 1)
4x β 12 = y + 1
4x β y β 13 = 0.......................(2)
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ALGEBRA