Page 210 - Buku Paket Kelas 7 Matematika Semester 2

Alternatif Penyelesaian
a. AB= AB= AD=
b. BE= = =
AD
10 cm, maka, 10 cm
AB2 +AE2 102 −62 100−36
BC= DC
BC = 17 cm, maka, BC = 17 cm
=
BE = 8 cm
sehingga BD = 2 × BE =2 × 8
BD = 16 cm
EC = BC2 −BE2 = 172 −82
= 289−64
= 225 EC = 15 cm
AC =AE+EC = 6 + 15
= 21 cm
202 Kelas VII SMP/MTs
64
Semester 2