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KUNCI JAWABAN
Pilihan Ganda
1. e 11. a
2. e 12. e
3. b 13. b
4. c 14. d
5. b 15. c
6. d 16. a
7. d 17. c
8. e 18. c
9. a 19. b
10. e 20. d
Essay
1. Diketahui
Massa terlarut = 15 gram Mr = 60 Ditanya : Titik beku larutan?
P = 250 gram kf air = 1,86
Penyelesaian
∆ = ∙ ∆ = −
°
15 1000 1,86 = 0 −
∆ = ∙ ∙ 1,86
60 250
1 = −1,86℃
∆ = ∙ 4 ∙ 1,86
4
∆ = 1,86
2. Diketahui
Mr glukosa = 180 Mr urea = 60 Suhu urea = 27°C = 300°K
Volume glukosa = 800 mL Volume urea = 300 mL Ditanya : Titik beku larutan?
Massa glukosa = 5 gram Massa urea = 0,6 gram
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