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                                                P > P
                                                 L1   L2




                                                         P             P
                                                          s             L1



                                                                Q
                                                                 v1








                                                         P s           P L2

                                  Q
                                    s
                                    P                           Q
                                     relief
                                                                 v2





                              FIGURE 7.58: An example illustrating the need for pressure compensator valves in multi
                              function parallel circuits.


                              goes into each cylinder depends on the load pressure. More flow will go to the circuit with
                              the smaller load pressure, and the flow ratio is
                                                                 √
                                                           Q v1    p − p l1
                                                                    s
                                                               = √                              (7.211)
                                                           Q v2    p − p l2
                                                                    s
                              For instance, let p = 3000 psi, p = 2000 psi, p = 1000 psi, same size valves, and same
                                                                    l2
                                            s
                                                        l1
                              valve spool displacement in each circuit. The flow rate distribution betwen the two
                              circuits is
                                                            √
                                                      Q v1    3000 − 2000   1
                                                          = √            = √                    (7.212)
                                                      Q v2    3000 − 1000    2
                              If the load condition changes, the flow rate will change: let p = 3000 psi, p =
                                                                                       s          l1
                              1000 psi, p = 2000 psi, and same size valves and valve spool displacement in each circuit.
                                      l2
                              The flow rate distribution betwen the two circuits under this load condition is
                                                            √              √
                                                      Q v1    3000 − 1000    2
                                                          = √            =                      (7.213)
                                                      Q v2    3000 − 2000   1
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