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                              Example    Let us consider an electrohydraulic (EH) motion axis with the following
                              parameters for the cylinder and load.
                                                            A he  = 2.0in 2                     (7.298)
                                                            A = 1.0in 2                         (7.299)
                                                              re
                                                              L = 20 in                         (7.300)
                                                             W = 1000 lb                        (7.301)
                              Let us consider the natural frequency at the mid-stroke point,

                                                        V  = A ⋅ L∕2 = 20 in 3                  (7.302)
                                                         he   he
                              and
                                                        V = A ⋅ L∕2 = 10 in 3                   (7.303)
                                                         re
                                                              re
                                                                                      5
                              Let us approximate the bulk modulus of hydraulic fluid to be 2.5 × 10 psi. The weight of
                                                                                            2
                              the rod and load W = 1000 lb, hence the mass, M = W∕g = 1000 lb∕386 in∕s . The open
                              loop natural frequency of the EH axis when the cylinder is at mid-stroke point is
                                                    √
                                               w =    K∕M                                       (7.304)
                                                n
                                                    1000       2              2
                                                M =      lb∕(in∕s ) = 2.59 lb∕(in∕s )           (7.305)
                                                     386
                                                            (  2    2  )
                                                              2    1       2  2 2  3
                                                          5
                                                K = 2.5 ⋅ 10 ⋅   +     lb∕in (in ) ∕in          (7.306)
                                                              20   10
                                                          4
                                                  = 7.5 ⋅ 10 lb∕in                              (7.307)
                              Then,
                                                     √
                                                 w =   K∕M                                      (7.308)
                                                  n
                                                     √
                                                                               2
                                                             4
                                                   =   7.5 ⋅ 10 ∕2.59 (lb∕in)∕(lb − s ∕in)      (7.309)
                                                   = 170 rad∕s                                  (7.310)
                                                   = 27 Hz                                      (7.311)
                              Therefore, a closed loop controller should not attempt to reach a bandwidth higher than

                                                       w bm  < (1∕3 ⋅ w ) = 9.0 Hz              (7.312)
                                                                   n
                              This particular EH motion axis cannot accurately follow cyclic small motion commands
                              with a frequency higher than 9.0Hz.


                       7.8 LINEAR DYNAMIC MODEL OF A ONE-AXIS HYDRAULIC
                             MOTION SYSTEM

                              Linear dynamic models assume that the hydraulic system operates about a nominal oper-
                              ating condition, that is the valve is operating about the null position with small movements
                              (Figure 7.64). Figure 7.80 shows a block diagram of a closed loop electrohydraulic (EH)
                              control system. Figures 7.81, 7.89, and 7.90 shows a closed loop position control (position
                              servo control) version of the system. Figure 7.82 shows a closed loop force control (force
                              servo loop) version of the system. Figure 7.91 shows a one-axis EH motion system where
                              the load pressure is regulated by the control element instead of the load position.
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