Page 574 - Mechatronics with Experiments
P. 574

JWST499-Cetinkunt
            JWST499-c07
                       560   MECHATRONICS  Printer: Yet to Come                      October 9, 2014 8:41 254mm×178mm
                                5. Different damping in the cylinder and load dynamics, c .
                                                                               p
                                6. Gains of PID controller; especially K value since velocity can reach large values for
                                                                d
                                   very short periods of time due to high frequency content.
                              Remark on “Dither” Signal in Hydraulic Control       There are two physical
                              sources of hysteresis in a hydraulic valve:
                                1. stiction friction,
                                2. electromagnetic hysteresis.
                              Electromagnetic materials have hysteresis. Let us assume that current is zero and magnetic
                              field is zero in a solenoid. When current is applied from zero to a finite value, a magnetic
                              field will develop approximately proportional to the current magnitude. When the current
                              is reduced back to zero, the magnetic field will not be exactly zero, but some residual field
                              will be left. This is the nature of electromagnetism and materials used in electromagnetic
                              actuators such as solenoids.
                                   Stiction friction presents a position control problem for valves. Due to stiction friction,
                              when the control signal (current) is small, the spool movement may be prevented. In order
                              to avoid this, it is very common in hydraulic circuits to add (“superimpose”) a dither signal
                              to the regular control signal in order to keep the valve spool moving about a nominal
                              operating condition.
                                   The dither signal is a periodic signal (i.e., sinusoidal) with a frequency typically in
                              the range of 100 Hz to 300 Hz, and its magnitude is in the range of 2–10% of the maximum
                              current signal,
                                                     i dither  = A dither  ⋅ sin(2   w dither  t)  (7.638)
                              where A dither  = 0.02 ∼ 0.10 ⋅ i max , and w dither  = 100 ∼ 300 Hz. The frequency and magni-
                              tude of the dither and its magnitude selection depends on the specific type of valve appli-
                              cation and is mostly determined by experimentation. The key is that the dither frequency
                              should be large enough not to affect the normal position response within the bandwidth
                              of the valve, but small enough still to cause some motion to break the stiction friction.
                              The dither signal can either be generated digitally in software or by an analog operational
                              amplifier circuit and added to the normal current signal.

                              %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
                              % Filename: EH_Servo_Sim.m
                              global  D_p  w_shaft p_max
                              global  Q_rv  x_vmax T_vmax p_r c_v  w_n  tau_a  K_a  K_t  i_v  x_v
                              global  beta  V_hose_pv  V_hose_va  V_hose_vb  A_a A_b  l_cyl m_p  c_p m_l
                                           F_load

                              global  Q_p  Q_v   Q_r
                              global  p_p  p_a   p_b  p_t
                              global y_d  ydot_d y  ydot  K_fb  K_p  K_i  K_d  u_i  i_cmd

                              % Parameters of the components of the  EH hydraulic circuit

                                 D_p = 20 ∗ 10ˆ-6  ;  % mˆ3/rev
                                 p_max = 20.685 ∗10ˆ6 ;  % [N/mˆ2] = Pa
                                 x_vmax = 10 ∗ 10ˆ-3 ; %  m
   569   570   571   572   573   574   575   576   577   578   579