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                        JWST499-Cetinkunt
            JWST499-c07
                                                            ELECTROHYDRAULIC MOTION CONTROL SYSTEMS  567
                                                y 1                   × 10 6  P  (head-end pressure)
                                                                             he
                                0.2                                  2
                                  0                                  1
                                –0.2                                 0
                                   0       5        10       15       0        5       10       15
                                                y 2                   × 10 6  P  (rod-end pressure)
                                                                             re
                                0.2                                  2
                                  0                                  1

                                –0.2                                 0
                                   0       5        10       15       0        5       10       15
                                                y                               Load force
                                0.5             3                10 000

                                  0                               5000

                                –0.5                                 0
                                   0       5        10       15       0        5       10       15

                             FIGURE 7.106: Simulation results: hydraulic cylinder connected to a flexible base and load.
                             The position of each mass, pressure, and flow rate on both sides (head-end and rod-end) of the
                             cylinder.





                             where V (0), V (0) are the initial conditions of the head-end and rod-end volume of the
                                    he    re
                             cylinder when y (0) = y (0) = 0.0
                                          1      2
                                  Simulation results for the following model parameters and initial conditions are
                             shown in Figure 7.106. The model parameters used in the numerical simulations are


                                                       m = 1000 kg                             (7.652)
                                                        1
                                                       m = 100 kg                              (7.653)
                                                        2
                                                       m = 1000 kg                             (7.654)
                                                        3
                                                             5
                                                       k = 10 N∕m                              (7.655)
                                                        1
                                                             6
                                                       k = 10 N∕m                              (7.656)
                                                        3
                                                       c = 1000 N∕(m∕s)                        (7.657)
                                                        1
                                                       c = 1000 N∕(m∕s)                        (7.658)
                                                        3
                                                                 8
                                                           = 7.0 ⋅ 10 N∕m 2                    (7.659)
                                                      A  = 0.01 m 2                            (7.660)
                                                       he
                                                      A = 0.005 m 2                            (7.661)
                                                        re
                                              C A   (x (t)) = 0.01 ⋅ (x − x )                  (7.662)
                                               d1 he1  s          s   db
                                              C A   (x (t)) = 0.01 ⋅ (x − x )                  (7.663)
                                                                  s
                                                                      db
                                                      s
                                               d1 re1
                                              C A   (x (t)) = 0.01 ⋅ (x − x )                  (7.664)
                                                                  s
                                               d2 he2
                                                                      db
                                                      s
                                              C A   (x (t)) = 0.01 ⋅ (x − x )                  (7.665)
                                                                      db
                                                      s
                                                                  s
                                               d2 re2
                                                      x db  = 10% deadband in percentage of    (7.666)
                                                               maximum spool travel            (7.667)
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