Page 700 - Mechatronics with Experiments
P. 700

686   MECHATRONICS
                              where we used the approximation
                                                     √           x
                                                       1 − x ≃ 1 − ;  for  x ≪ 1
                                                                 2
                              The poles are
                                                            K K
                                                             T e
                                                      p =−                                      (8.294)
                                                       1
                                                            J R
                                                             T a
                                                                     (      )
                                                            −2R J +   2L a K T K e
                                                                a T
                                                      p =−              R a                     (8.295)
                                                       2
                                                                  2L J
                                                                    a T
                                                            R a  K K
                                                                  T e
                                                         =−    +                                (8.296)
                                                            L a  J R
                                                                  T a
                              Since  R a  ≫  K T K e  the second pole is approximately
                                   L a  J T R a
                                                                    R a
                                                              p ≃−                              (8.297)
                                                               2
                                                                    L
                                                                     a
                              The motor terminal voltage to motor speed transfer function can be approximated as
                                                                 (    )
                                                                   K T
                                                        ̇
                                                         (s)       J T L a
                                                            =                                   (8.298)
                                                       V (s)  (s − p )(s − p )
                                                        t
                                                                   1
                                                                         2
                                                                   (  )
                                                                     1
                                                                    K e
                                                            =                                   (8.299)
                                                              (   s + 1)(   s + 1)
                                                               m       e
                              where
                                                      1   J R
                                                           T a
                                                  =−    =       mechanical time constant        (8.300)
                                                m
                                                     p    K k
                                                      1    T e
                                                      1   L a
                                                   =−   =     electrical time constant          (8.301)
                                                e
                                                     p    R
                                                      2    a
                              and the mechanical time constant    is much larger than the electrical time constant    for
                                                          m                                       e
                              most motors. The motor speed is also influenced by disturbance or load torque. The transfer
                              function including the load torque can be derived as follows
                                                                           (     )
                                                      K T                    L a s+R a
                                        ̇
                                          (s) =  (   ) J T L a  (  )V (s) −  (  ) J T L a  (  )T (s)  (8.302)
                                                                 t
                                                                                         l
                                              2
                                                                       2
                                             s +   R a  s +  K T K e  s +  R a  s +  K T K e
                                                   L a     J T L a         L a     J T L a
                                                    1                         1  K T
                                                                    (   s + 1)R a
                                                                      e
                                                    K e                      K T J T L a
                                           =                V (s) −   (   )   (    )T (s)       (8.303)
                                                             t
                                                                                      l
                                             (   s + 1)(   s + 1)
                                                                   2
                                               m       e           s +  R a  s +  K T K e
                                                                        L a     J T L a
                                                    1                1 R a
                                                                        (   s + 1)
                                                                          e
                                                    K e             K e K T
                                           =                V (s) −              T (s)          (8.304)
                                                             t
                                                                                  l
                                             (   s + 1)(   s + 1)  (   s + 1)(   s + 1)
                                               m       e            m       e
                                                    1                1 R a
                                        ̇
                                          (s) =     K e     V (s) −  K e K T  T (s)             (8.305)
                                                                           l
                                                             t
                                             (   s + 1)(   s + 1)  (   s + 1)
                                                       e
                                               m
                                                                    m
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