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36                                     2  Feedback Control Theory Continued


            Fig. 2.15   Bode diagram   5
            for the open loop transfer
            function in the form of   –10
             / ye =  0.25 / (0.25s  s  2  . The   Amp(ω)  –25
              +  0.1s + 1)         –40
            phase angle reaches – 270°  0.1              1                  10
                                                         ω
                                     0
                                    -90
                                 Ψ(ω)  –180


                                  –270
                                      0.1                1                  10
                                                         ω


            seen at the intersection point there is an exact point, which has happened by chance.
            Otherwise more points are needed to be calculated. The phase angle between a unity
            circle and Nyquist plot occurs at phase angle of 90°.



            2.7   Bode Diagram


            Bode diagram is an alternative way of presenting the frequency response of open
            loop transfer function. The amplitude ratio in decibels is plotted against frequency
            in logarithmic scale. On the same diagram or on separate diagram underneath the
            amplitude ratio curve, the phase angle is also plotted against the frequency in loga-
            rithmic scale. A typical Bode diagram is shown in Fig. 2.15.
              The phase angle reaches – 270° for a third order transfer function as frequency is in-
            creased. The graph of Fig. 2.15 shows that the phase angle reaches – 180° and then the
            phase angle is reduced. This is because the acos function only supports 180 and – 180°.
            The phase angle above –180° minus the reduction from –180°. The absolute phase
            angle is above –180°. To find the direction of phase angle it is better to study the real
            and imaginary values as shown below the equations used to plot the Bode diagram.

                             i:=−  1
                                              0.1
                             z( ) :ω
                                  (0 i ω+  · ) · ( 0.25ω−  2  + 0.li · ω+ 1)
                                        ω
                               ω=
                             x( ) : Re(z( ))
                               ω=
                                        ω
                              y() : Im(z())
                                ω=
                             M( ) :  ( ( ))x ω  2  + ( ( ))y ω  2
                                             x( ) ω
                                     − 180acos
                             ψω              M( ) ω
                                ( ):=
                                          π
                                              ω
                                  ω=
                             Amp( ) : 20log(M( ))
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