Page 15 - classs 6 a_Neat
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EXAMPLE 3: Simplify: 16 -[11-{8 ÷ (17 + 3 × 2 -19)}) EXAMPLE: 6. Simplify, 1 1 1 1 1 1
3 ÷ 1 − 2 2 −− 6
2
4
4
4
SOLUTION: The given expression SOLUTION We have:
= 16 - [11 - {8 ÷ (17 + 3 × 2 -19)
= 16 - [11 - {8 ÷ (17 + 6 -19)
1
1
1
1
= 16 - [11 - {8 ÷ 4] = 16 - [11 - 2] 3 ÷ 1 − 1 2 −− 1
= 16 - 9 = 7. = 4 4 2 2 4 6
EXAMPLE 4: Simplify: 14 - [12 - {9 - (7 - 6 - 2)}) 13 5 1 5 1 1
= ÷ − −−
SOLTIONS: The given expression 4 4 2 2 4 6
= 14 - [12 -{9-(7 -6-2)}] 13 5 1 5 3 2 −
= 14 - [12-{9-(7 - 4)} ] [removing vinculum] = 4 ÷ 4 − 2 2 − [removing bar]
= 14 - [12-{9-3}] [removing parentheses] 12
= 14 - [12-6] [removing braces] 13 ÷ 5 − 1 5 − 1
= 14 - 6 [removing square brackets] = 4 4 2 2 12
= 8.
= 13 ÷ 5 − 1 30 1 −
1 2 3 1 5 4 4 2 12
EXAMPLE 5. Simplify: 5 of − +÷
2 3 5 2 11 = 13 ÷ 5 −× [removing parentheses]
1 29
SOLUTION: The given expression 4 4 2 12
11 2 3 1 5
= of − +÷ 13 5 29 13 30 29 − [removing braces]
2 3 5 2 11 = 4 ÷ 4 − 24 = 4 ÷ 24
11 10 9 − 1 5
= of +÷ = 13 ÷ 1
2 15 2 11 4 24
11 1 1 5
= of +÷ [removing parentheses]
2 15 2 11 = 13 23 ÷ = 78 [removing square brackets]
11 1 5 4 1
= +÷ [removing ‘of’]
30 2 11
11 1 5
= + × [removing’+’]
30 2 11
11 5
= + [removing ‘x’]
30 11
11 33 = 44
+
= [performing addition]
30 30
22 7
= = 1 ⋅
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