Page 97 - classs 6 a_Neat

EXAMPLE 4: Ramesh purchased a book. a pen and a noteboolcfor ₹ 165.35. ₹ 72 and ₹ 14.85 EXAMPLE 6. Monika went to the market with ₹ 3000 in cash. Out of this money she purchased one
respectively. I-low much money will he have to pay to the shopkeeper for frock,
these items? one toy and one bag costing ₹ 578. 75, ₹ 309 and ₹ 1862.85 respectively.
How much money is left with her?
SOLUTION: Cost of a book = ₹ 165.35 SOLUTION: Cost of one frock = ₹578.75
Cost of a pen = ₹ 72.00 Cost of one toy = ₹309.00
Cost of a notebook = ₹ 14.85 Cost of one bag = ₹1862.85
Total cost = ₹ 252.20 Total cost =₹ 2750.60
Total money to be paid by Ramesh = ₹ 252.20 Total cash in hand = ₹3000.00
EXAMPLE 5: The weight of an empty gas cylinder is 18 kg 75 g. The weight of the gas contained in Total money spent = - ₹ 2750.60
it is 12 kg 350 g. What is the total weight of the cylinder filled with gas? Balance = ₹249.40
Hence, the money left with Monika = ₹249.40.
SOLUTION: Weight of an empty cylinder = 18.075 kg
Weight of the gas filled in it = 12.350 kg EXAMPLE 7. The distance between Ric ha ·s house and her school hostel is 61 km. For reaching her
Total weight = 30.425 kg house from the hostel. she covers 54 km 860 m by taxi. 5 km 65 m by tonga and the
Hence. the total weight of the cylinder filled \vith gas = 30.425 kg = 30 kg 425 g. rest of the distance
by rickshaw. How much distance did Richa cover by rickshaw?
EXAMPLE 6: Subtract 28.65 from 73.
SOLUTION: Distance covered by taxi = 54.860 k m
SOLUTION: Converting the given decimals into like decimals, we get 28.65 and 73.00. Distance covered by tonga = + 5.065 km
Writing them in column form with the larger one at the top and subtracting, we get: Total distance covered by taxi and tonga - =- - - -5-9.925 km
73.00 Total distance to be covered by Richa = 61.000 k m
-28.65 Distance covered by taxi and tonga = - 59.925 km
44.35 distance covered by rickshaw = 1.075 km
Hence, 73 -28.65 = 44.35. Hence. the distance covered by rickshaw = 1.075 k m
= 1 km 75 m.
EXAMPLE 7: Simplify: 53.5-34.68 + 64.75 - 28.9
EXAMPLE 8. The total weight of a bag containing 13 kg 750 g of potatoes and 8 kg 80 g of
SOLUTION: Converting the given decimals into like decimals, tomatoes is 22 kg 200 g. How much is the weight of the empty bag?
and adding and subtracting as shown alongside, the given expression SOLUTION: Weight of potatoes = 13 kg 750 g = 13.750 kg
= 53.50 -34.68 + 64. 75 -28.90 Weight of tomatoes = 8 kg 80 g = + 8.080 kg
= (53.50 + 64. 75) -(34.68 + 28.90) = 118.25 -63.58 Total weight of vegetables = 21.830 kg
= 54.67. Total weight of the bag and vegetables = 22.200 kg
EXAMPLE 8: Ramesh purchased a book worth t 146. 75 from a bookseller and gave him a Total weight of vegetables in it = - 21.830 kg
500-rupee note. Weight of the empty bag = 0.370 kg
How much balance did he get back? Hence, the weight of the empty bag = 0.370 kg
= 370 g.
SOLUTION: Total money paid = ₹ 500.00
Cost of the book = -₹146. 75 EXAMPLE 1: Add 3.2, 47.26 and 3.832
Balance = ₹ 353.25 EXAMPLE 2: Subtract 42.375 from 6.7
Hence, the balance received by Ramesh=₹ 353.25
PRACTICE EXERCISE 6.3
EXAMPLE 9: The weight of a cylinder filled with gas is30 kg.if the weight of the empty cylinder ts
14 kg 80 g, find the weight of the gas contained in it. 1. Add the following decimals.
a. 6.78, 23.5 and 42.8 b. 0.009, 9.9 and 99.09 c. 41.5, 5.62, 9.638
SOLUTION: Weight of the cylinder filled with gas = 30.000 kg d. 100.5, 10.5, 1.005 e. 12.8, 12.71, 12.395
Weight of the empty cylinder = -14.080 kg
Weight of the gas in the cylinder = 15.920 kg 2. Subtract the following decimals.
Hence, the weight of the gas = 15.920 kg. a. 12.65 from 29.860 b. 21.11 from 211.111 c. 437.5 from 563.895
d. 108.032 from 868.8 e. 46.532 from 50.1