Page 24 - E-MODULE TURUNAN FUNGSI ALJABAR
P. 24

E-MODULE                                                                             Kelas XI
               e


                                       KUNCI JAWABAN LATIHAN



               1.     = (   + 1)(   − 1)           ℎ    =      +      +     
                                                                     2
                                                      ′
                                                             4
                                     3
                           2
                                               ?
                Jawab
                   = (   + 1)(   − 1)
                       2
                                 3
                   =    +    −    − 1
                      5
                            3
                                  2
                                2
                  ′
                                               ′
                                                              2
                         4
                   = 5   + 3   − 2       ↔     =      +      +     
                                                      4
               Maka    = 5 ; b = 3; c = -2

                              2
               2.    (  ) =    (3   − 1)  turunan pertama adalah
                                         3
                    Misalkan    =            = 2  
                                           ′
                                     2
                                            = (3   − 1)      = 3(3   − 1) (3) = 9(3   − 1)
                                                                  2
                                                                                      2
                                                   ′
                                               3
               Maka    (  ) =    .    +   .   ′
                                 ′
                        ′
                  ′
                                                         2
                                            2
                   (  ) = 2  (3   − 1) +    (9(3   − 1) )
                                      3
                   (  ) = 2  (3   − 1) + 9   (3   − 1) )
                  ′
                                      3
                                             2
                                                        2
                                                        2
                   (  ) = (3   − 1) (2  (3   − 1) + 9   )
                                   2
                  ′
                    (  ) = (3   − 1) (6   − 2   + 9   )
                                                      2
                                         2
                  ′
                                    2
                  ′
                                          2
                   (  ) = (3   − 1) (15   − 2  )
                                   2
                   (  ) =   (15   − 2  )(3   − 1)
                                                  2
                  ′
                                2

               3.    (  ) = 2   − 5   + 1
                               3
                        (2) = ⋯ ?
                      ′
                        Jawab
                             2
                   ′(  ) = 6   − 5
                               2
                    ′(2) = 6(2) − 5
                  ′(2) = 6.4 − 5

                   ′(2)  = 24 − 5   ↔    ′(2) = 19


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