Page 129 - AFCAT Solved Papers 2011 - 2019 SSBCrack eBook

Work done in three days (When A is assisted by B and 35. (d) Let x be the cost price of T.V.

1 1 2 1 loss = 15%
C on every third day) = + = = then, S.P. = x – 15% of x = 0.85x
10 10 10 5 1
Hence required number of days = 5 × 3 = 15 days. Profit = 15%
2
31. (c) Distance covered by man = D km then, S.P = x + 15% of x = 1.15x
Speed of Man in still water = x kmph total S.P = 0.85 x + 1.15x = 2x
Profit = 2x – 2x = 0
28 No profit, no loss
Speed of current = kmph
3 36. (c) Let D Km be the distance between A and B.
According to question,
D D 48
æ ö 25 + 4 = 5 60
D ç D ÷
+
28 - x = 3 ç ç 28 + x÷ ÷ 4 D 25D - 29
3 è 3 ø 100 5
29D 29
28 æ 28 ö =
Þ + x = 3 ç - x ÷ 100 5
3 è 3 ø
D = 20 Km
28 37. (*) Let 'x' be the length of the train.
Þ 4x = 2 ´
3 Let 'S' be the speed of train.
Distance travelled by train to cross the platform
14 2
Þ x = or 4 Kmph = ( x + 200)m
3 3 According to question
32. (c) Let speed of stream be x Kmph. (x + 200) = S × 10 sec. ...(1)
Then, Distance travelled by train to cross he telegraph post
26 14 = xm
+
-
10 x = 10 x According to question
260 – 26x = 140 + 14x x = S × 5 sec. ...(2)
40x = 120 Puting 'x' value in (1) from (2)
x = 3 (5S + 200) = 10S
Speed of stream is 3 Kmph. 200 = 10S – 5S = 5S
33. (a) S.I. = 2P – P = P S = 40 m/s
´
´
P R 16 8
P =
100 S = 40 ´ 18 = 144 km/hr..
5
25
R = % None of the option is matching.
4
38. (c) Let x and y be the rate of sugar per Kg and quantity of
25 sugar.
P ´ ´ 8 P
(S.I) For 8 years = 4 = æ 20 ö
100 2 xy = ç è x + ´ x y'
÷
ø
P 3P 100
Amount = P + =
2 2 xy = 6x y'
Amount increased by 1½ times. 5
æ 10 ö 2t y' = 5 y = y - y
ç 2 ÷ 6 6
=
34. (b) 926.1 800 1+ ç ÷
2
ç è 100 ÷ ø Reduction in consumption = 100 = 16 %
6 3
2t 39. (d) A = B – 20% of B = 0.8 B
9261 = æ 21ö B = C – 15% of C = 0.85 C
8000 ç è 20ø ÷
A = 0.8 × 0.85 C = 0.68 C
-
-
æ 21ö 3 æ 21ö 2t 3 1 C A C 0.68C 32
ç è 20ø ÷ = ç è 20ø ÷ Þ t = 2 years or 1 years. A ´ 100 = 0.68C ´ 100 = 68 ´ 100 = 47.05%
2