Page 139 - AFCAT Solved Papers 2011 - 2019 SSBCrack eBook

10km
49. (c) Speed of train = = 50km/h
12/60h æ 1 1 1 ö 1 1 1 1 1
2 ç + + ÷ = Þ + + = ...(4)
Speed is decreased by 5 kmph then new Speed of the è x y z ø 8 x y z 16
train will be 45 kmph A,B and C together complete the work in 16 days.
10 2 10 5
Time taken to cover 10 km, t = = h In 10 days they completed = Part
45 9 16 8
Time taken = 13min. 20 sec 5 3
50. (b) Let A finish the work in x days Remaining work = 1– =
B finish same work in 3 x days 8 8
3x – x = 10 Þ x = 5 days Subtracting equ (2) from (4)
B finish the work in 3×5 = 15 days we get, = 1 1 or x = 48
51. (c) Let Arun's weight be x kg x 48
According to Arun, 65< x < 72 A alone can finish the Remaining work in
According to Arun's brother, 60 < x < 70 3
=
According to Arun's mothers, x < 68 8 ´ 48 18days
The value satisfying all the above Conditions are 66 56. (d) Skilled workers : Unskilled workers : Clerks = 8:5:1
and 67
Ratio of the respective wages = 5:2:3
æ 66 67 ö + Hence, the amount must be paid in the ratio
\ Required average = ç è 2 ÷ ø = 66.5kg 8×5 : 5×2 : 1×3 = 40 : 10 : 3

52. (d) Let in third yearly examination he Secure x % Sum of the ratios = 40 + 10 + 3 = 53
If the total amount is ` 53, the skilled workers get ` 40.
+
+
45 55 x
Then, = 60 If the total amount is ` 318, the skilled worker will get
3
100 + x = 180 = 40 ´ 318 ` 240
x = 80 53
To secure 60% average, he has to get 80% 10
Unskilled workers get = ´ 318 = ` 60
80 53
=
80% of 500 = ´ 500 400marks
100 3 ´
53. (b) Area of towel = l×b =100 cm × 50cm = 5000 cm 2 and clerk get = 53 318 = ` 18
Now, length decreased by 20% and breadth decreased 57. (d) 3 leaps of dog = 4 leaps of cat
by 10% 16
l = 100 – 20% of 100 = 80cm \ 4 leaps of dog = 3 leaps of cat
b = 50 – 10% of 50 = 45cm
New area = l × b = 80cm × 45cm = 3600cm 2 16 :5 16:15
=
2
Change in area = (5000 – 3600) cm = 1400 cm 2 \ the rate of dog : rate of cat = 3
rate of cat : rate of dog = 15:16
1400
=
% change in area = ´ 100 28%
8
5000 58. (a) Each one receive apple
54. (b) 95.75 × 0.02554 = 2.445455 3
There are 6 digits to the right of the decimal point in the 8 1
product of 95.75 and 0.02554. Ram gave = 3 – = apple
55. (b) Let A,B and C individualy complete the work in x,y and 3 3
z days respectively. 8 7
Shiv gave = 5 – = apples
1 + 1 = 1 3 3
x y 30 ...(1) 1 7
\ Ram : Shiv = : = 1: 7
3 3
1 + 1 = 1
1
y z 24 ...(2) Ram got = 8× = ` 1
8
1 + 1 = 1 7
z x 20 ...(3) Shiv got = 80 × = ` 7
8