Page 177 - AFCAT Solved Papers 2011 - 2019 SSBCrack eBook

2
2
36. (c) The endocrine system refers to the collection of glands a + b = 58
3
of an organism that secrete hormones directly into the Now, a + b = (a + b) (a + b – ab)
3
2
2
circulatory system to be carried toward a distant target = (10) (58 – 21)
organ. The major endocrine glands include the pineal = 10 × 37 = 370
gland, pituitary gland, pancreas, ovaries, testes, thyroid
gland, parathyroid gland, hypothalamus, 45. (b) a = 17
+
gastrointestinal tract and adrenal glands. a b 23
37. (d) The middle lamella is a pectin layer which cements the 23a = 17a + 17b
cell walls of two adjoining cells together. Plants need 6a = 17b
this to give them stability and so that they can form 17
plasmodesmata between the cells. It is the first formed a = 6 b
layer which is deposited at the time of cytokinesis. The
cell plate that is formed during cell division itself 17 b b 17 + 1
+
+
develops into middle lamella or lamellum. The middle a b = 6 = 6
-
lamella is made up of calcium and magnesium pectates. a b 17 b b 17 - 1
-
In plants, the pectins form an unified and continuous 6 6
layer between adjacent cells.
+
a b 23
38. (d) The effective nuclear charge is the net positive charge Þ =
-
experienced by an electron in a multi-electron atom. a b 11
The term "effective" is used because the shielding 2 598- 2
effect of negatively charged electrons prevents higher 46. (c) (598 479 ) + ( - ) 479
orbital electrons from experiencing the full nuclear 598 479´
2
2
charge by the repelling effect of inner-layer electrons. Þ (598) + (479) + 2 × 598 × 479
The effective nuclear charge experienced by the outer 2 2
479
598 -
´
´
- ( ) ( ) + 2 598 479
shell electron is also called the core charge. It is possible
to determine the strength of the nuclear charge by 598 479´
looking at the oxidation number of the atom. 4 598 479
´
´
2
2
41. (b) (40) – (32) = 1600 – 1024 = 576 Þ 598 479
´
Hence, 24 is the required number. Þ 4
42. (c) Less capacity, more buckets. (Indirect proportion) 47. (c) Total expenditure spent on four months
\ 5 : 15 : : 7 : x
= 4 × 225.25 = ` 901
5 = 7 Total expenditure spent on next five months
15 x
= 5 × (225.25 + 20.75)
x = 21
Hence, 21 buckets will be needed to fill the same tank. = 5 × 246 = ` 1230
43. (a) Let ‘x’ be the weight g empty vessel and ‘y’ be the Total expenditure for 12 months
weight of full vessel. = ` [901+ 1230 + 700] = 2831
x + y = 27.5 ...(1)
669
=
y Required % = ´ 100 19.11%
x + = 12.26 3500
4
48. (d) Let the present age of P and Q be 2x and 3x.
4x + y = 4 × 12.26 ...(2) According to question
Subtracting equation (1) from (2)
4x – x = 49.04 – 27.5 2x 18 = 4
+
+
3x = 21.54 3x 18 5
x = 7.18 kg 10x + 90 = 12x + 72
44. (a) Given, a + b = 10 2x = 18
Squaring on both sides
2
2
a + b + 2ab = 100 x = 9
2
2
a + b = 100 – 2 × 21 Present age of Q = 9 × 3 = 27 years