Page 43 - AFCAT Solved Papers 2011 - 2019 SSBCrack eBook

528 When the price is increased to 1 she has to
So, cost of one egg should be = 6
88 25
i.e. Rs. 6 reduce 125
So the retailer will sell his egg at cost of Rs.6 Rate by which consumption decreases =
58. (d) On Rs 100, interest charged for 1 year 25 × 100
is Rs 15. 125
=20 percent
So, on Rs. 10,000, interest charged 63. (c) Let the positive number be .
15
× 10000 = Rs. 1500 According to the question,
100
Interest for 2 years = Rs 1500 × 2 = Rs. 3000 × = + ×2000
59. (c) Speed of the boat upstream = 9–3 = + 20 100
2
= 6 km/hr − 21 = 0
2
Speed of the boat downstream = 9+3 Either, = 0, = 21
= 12 km/hr
21 is the possible value.
Let distance between A and B be x kms. Then square of 21 is 441
So, time taken to travel x km upstream by boat 64. (b) Let the bike's initial cost be x
= x/6 hrs. And then car's initial cost be 5x
And time taken to travel x kms downstream= After the increase,
x/12 hrs. Bike’s price = 1.2x
According to the question, Car’s price = 5.75x

+ = 3 Initial total cost of 5 cars and 10 bikes,
6 12
1 1 = 25x+10x = 35x
[ + ] = 3 New cost = 28.75x+12x = 40.75x
6 12
= 4 × 3 = 12 Change in cost
So, distance between A and B is 12 km. = (40.75x − 35x) = 5.75x
16 18 5.75x × 100 3
60. (b) (256)100 × (16)100 % change = = 16 %.
4 9 35 7
2
= (16 )25 × (16)50 65. (b) The average weight of the bars given to
8 9 Brennan (light) < the average weight of the
= (16)25 × (16)50
8 9 25 bars given to Blair < the average weight of the
+
= (16)25 50 = (16)50 bars given to Maya (heavy).
1
= (16)2 = √16 = 4 Let the total weight of all the bars be X.
81 The weight of the bars given to Brennan,
61. (d) Note that 0.0081 =
10000 =45% of = 0.45
√0.0081 = √ 81 The weight of the bars given to Maya,
10000 =26% of = 0.26
√ 81 9
= = = 0.09 The weight of the bars given to Claire = rest
√ 10000 100
62. (c) Let the price before increase be 100 = 29% = 0.29
Increased price = 25percent of 100 The average weight of the bars given to
25 Brennan, = Weight/number of bars
× 100 + 100 = 125 0.45
100 = 24
When the price is increased to 125 she has to The average weight of the bars given to Maya =
reduce 25 Weight/number of bars