Page 67 - AFCAT Solved Papers 2011 - 2019 SSBCrack eBook

[on squaring]
1 1 19 37. (C)
4
⟹ + = 9 + =
16 2 2 2 8 2
30. (B) 2916 = (1 + 100 )
Total distance = 100 km 2916
1
5
Total time = 50 + 40 + 10 = 1 + 1 + = ℎ = (1.08) 2 = 2500
50 40 20 2 2
100 × 2 2500 × 9 × 3
∴ = = 40 ℎ . . = = 675
5 100
31. (B) Let total number of workers be n total salary 38. (B)
of all workers = 8000 n total salary of 7 A : B = 2 : 3 = 8 : 12
technicians = 7 × 12000 = 84,000 total salary of B : C = 4 : 5 = 12 : 15
remaining workers = (n – 7) × 6000 84000 + (n – A : B : C = 8 : 12 : 15
7) × 6000 = 8000 n 84 + 6n – 42 = 8n 42 = 2n n = Sum of ratio = 35
21 ∴ ℎ = 8 × 700 = . 160
′
32. (B) Let the monthly salary of A be x,, monthly 12 35
′
salary of B is (40000 – x). Savings of A = (100 – ℎ = × 700 = . 240
35
85)% of x = 0.15x Savings of B = (100 – 95)% of 15
′
(40000 – x) = 0.05 (40000 – x) 0.15 x = 0.05 ℎ = 35 × 700 = . 300
(40000 – x) 0.15x + 0.05x = 40000 × 0.05 0.2x = 39. (C)
2000 x = 10000 OR (A + B)’s 1 day’s work = 1/8
15 5 (B + C)’s 1 day’s work =1/12
× =×
100 100 (C + A)’s 1 day’s work =1/8
∴ : = 1:3 On adding, 2 (A + B + C)’s 1 day’s work
1
Salary of = 40000 × = 10000 1 1 1 3 + 2 + 3 8 1
4 = + + = = =
33. (C) 8 12 8 24 24 3
32000 ′ ′ 1
= 2 ∴ (A + B + C) s 1 day s work =
6
20
(1 − 100 ) Hence, the work will be completed in 6 days.
5 5 40. (D) Part of the tank filled by both pipes in two
= 32000 × × = 50000
4 4 hours
34. (D) 1 1 3 + 4 7
10 + 14 = 2 ( + ) = 2 ( 24 ) = 12
6
8
= = 12 7 5
12 Remaining part = 1 − =
= 13 12 12
13 − 12 1 Time taken by B in filling the remaining part
% = × 100 = 8 5 5 1
12 3 = × 6 = = 2 ℎ
35. (C) If the original price of article be Rs. x, then 12 2 2
80 130 41. (B) According to question, If P can complete a
× × = 416 work in 1 day, Q can complete the same work in
100 100
416 × 100 × 100 4 days. Hence, if the difference is 3 days, Q can
⟹ = = . 400
80 × 130 complete the work in 4 days.
36. (D) ⟹If the difference is 45 days, Q can complete
the work in 60 days
= (1 + ) 1
100 ∴ Q’s 1 day’s work = 60
5 1 1
⟹ 24000 = 12000 (1 + ) ∴ P’s 1 day’s work = 4 × =
100 60 15
5 ∴ (P + Q)'s 1 day's work
⟹ 2 = (1 + ) 1 1 (4 + 1) 5 1
100 = ( + ) = = =
20 15 60 60 60 12
4
⟹ 2 = (1 + ) = 16 ∴ P and Q together can do work in 12 days.
100
i.e. The sum amounts to Rs. 192000. 42. (D) Relative speed =