Page 88 - AFCAT Solved Papers 2011 - 2019 SSBCrack eBook

57. (b) Let principal = 100 276 100
´
Amount = 200 \ Obtain marks in percentage =
Rate = r% 600
Time = 4 years = 46%
Now, 46
\ Percentage average = 3 = 15.33%
t
æ
A = P 1 + r ö ÷
ç
è 100 ø 25
61. (b) Total valid votes = 6000 – 6000 × 100
æ r ö 4
=
200 100 1 + ÷ = 4500
ç
è 100 ø 55
Votes obtained by Biku = 4500´ = 2475
æ r ö 4 100
2 = ç 1+ ÷ ............(i)
è 100 ø Votes obtained by Mahtre = (4500 – 2475) = 2025.
If sum become 4 times in the time n years 62. (c) Let the number be x
According to question,
æ r ö n x 30
´
then, 4 = ç 1+ ÷ 91- = x
è 100 ø 100
9100 – 30x = 100x
n
2 = 2 æ ç 1 + r ö ÷ .............(ii) 130x = 9100
è 100 ø 9100
Using eqn (i) and (ii) we get \ x = = 70
130
2 63. (d) Let the number be x
é æ r ö 4 ù æ r ö n
ê ç 1 + ÷ ú = ç 1 + ÷ According to question,
ë è 100 ø ê ú û è 100 ø x 50
´
84 + = x
8 n 100
æ r ö æ r ö
ç 1 + ÷ = ç 1 + ÷ 8400 + 50x = 100x
è 100 ø è 100 ø 100x – 50x = 8400
Thus, n = 8 years 50x = 8400
58. (a) CP of 12 chocolates = ` 9 8400
9 \ x = = 168
CP of 1 chocolate = = 0.75 50
12 64. (a) A number is divisible by 9 when the sum of its digit is
Now, divisible by 9.
SP = ` 1, Profit = 0.25 So, (3 + 8 + 1 + A) = must be divisible by 9.
0.25 1 Thus smallest natural number be 6.
Profit% = ´ 100 = 33 % or, (3 + 8 + 1 + 6) = 18, this is divisible by 9.
0.75 3
59. (d) SP = 12, 000 100
1 65. (a) CP of 1st TV = 3000´ = 2608.69
12,000 115
CP = 0.75 = 16,000 Profit = SP – CP = 3000 – 2608.69 = 391.31
1
SP = 12, 000 Loss on 2nd TV = 391.31
Loss percentage = 10%
2
12,000
CP = = 10,000 Loss ´
2 1.2 Loss percentage = CP 100
So, total CP = 16000 + 10000 = 26, 000
total SP = 24, 000 10 = 391.31 ´ 100
So loss = 2000 CP
2000 391.31 100
´
\ loss percentage = ´ 100 \ CP =
26,000 10
= 7.6% = 3913.10 @ 3913
60. (a) Total marks in all subjects = (100 + 150 + 350) = 600 66. (d) Except (d), all animals are females.
Total marks obtained by student = 77 + 96 + 103 = 276
67. (c) Except (c), all are capital cities.