Page 100 - Services Selection Board (SSB) Interviews
P. 100

96                                                                                           Input Output
            12.  Which words numbers would be at seventh position      (b)  road jam hut for bus all stop 15 25 38 46 52 73
                from the left in step IV?                                 96
                (a)  base              (b)  at                        (c)  stop road jam hut for bus all 96 73 52 46 38 25
                (c)  35                (d)  the                           15
                (e)  53                                               (d)  jam hut for bus all 25 road stop 15 96 73 52 46
            13.  Which step number would be the following output?         38
                                                                      (e)  There will be no such step
                53 28 68 16 89 at 35 the here fun base camp
                (a)  There will be no such step                  17.  Which words numbers would be at 6th position from
                                                                      the left in step V?
                (b)  III               (c)  II                        (a)  25                (b)  stop
                (d)  V                 (e)  IV                        (c)  jam               (d)  all
            Directions (Qs. 14-18): Study the following               (e)  road
            information carefully and answer the given question:  18.  Which of the following would be step III?
            A word and number arrangement machine when given          (a)  hut for bus all 25 jam road 15 stop 38 96 73 52
            an input line of words and numbers rearrange them             46
            following a particular rule in each step. The following is an      (b)  for bus all 25 jam road 15 hut 38 stop 96 46 73
            illustration of input and rearrangement. (All the numbers     52
            are two-digit numbers)
                                                                      (c)  hut for bus all jam road 15 stop 38 96 73 52 46
                        [IBPS Common Written Exam PO (PO/MT)              25
            Input    : Sine 88 71 cos theta 14 56 gamma delta 26      (d)  for bus all 25 jam road 15 hut stop 38 46 96 73
            Step I    : cos sine 71 theta 14 56 gamma delta 26 88         52
            Step II    : delta cos sine theta 14 56 gamma 26 88 71     (e)  None of these
            Step III   : gamma delta cos sine theta 14 26 88 71 56  Directions (Qs. 19-23): Study the following
                                                                 information carefully and answer the given question:
            Step IV  : sine gamma delta cos theta 14 88 71 56 26  A word and number arrangement machine when given
            Step V   : theta sine gamma delta cos 88 71 56 26 14  an input line of words and numbers rearrange them
            Steps V is the last step of the arrangement the above input.  following a particular rule in each step. The following is an
            As per the rule followed in the above steps, find out in   illustration of input and rearrangement. (All the numbers
            each of the following questions the appropriate steps for   are two-digit numbers).   [RBI Grade B Officer]
            the given input.                                     Input    : gate 20 86 just not 71 for 67 38 bake sun 55
            Input for the questions                              Step I    : bake gate 20 just not 71 for 67 38 sun 55 86
            Input: for 52 all 96 25 jam road 15 hut 73 bus stop 38 46   Step II    : for bake gate 20 just not 67 38 sun 55 86 71
            (All the numbers give in the arrangement are two-digit   Step III   : gate for bake 20 just not 38 sun 55 86 71 67
            numbers)                                             Step IV  : just gate for bake 20 not 38 sun 55 86 71 67
                                                 th
            14.  Which words numbers would be at 8  position from   Step V   : not just gate for bake 20 sun 86 71 67 55 38
                the left in step IV?                             Step VI  : sun not just gate for bake 86 71 67 55 38 20
                (a)  15                (b)  road                 Steps VI is the last step of the  arrangement  the  above
                (c)  hut               (d)  jam                  input.
                (e)  stop                                        As per the rule followed in the above steps, find out in
            15.  Which step number would be the following output?  each of the following questions the appropriate step for
                bus all for 52 25 jam road 15 hut stop 38 46 96 73  the given input.
                (a)  There will be no such step                  Input: 31 rise gem 15 92 47 aim big 25 does 56 not 85
                (b)  III               (c)  II                   63 with moon
                (d)  V                 (e)  VI                   19.  How many  steps will  be required  to complete  the
            16.  Which of the following would be step VII?            rearrangement?
                (a)  stop road jam hut for bus all 15 96 73 52 46 38      (a)  Eight         (b)  Six
                     25                                               (c)  Seven             (d)  Five
                                                                      (e)  None of these
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