Page 80 - Services Selection Board (SSB) Interviews

76 Circular Arrangement
Solution for (8 – 12): 21. (c)
UCO 22. (a)

Dena BOI 23. (a)
C F G 24. (a)
H Canara 25. (b)
E A
PNB D B Solutions for (26–28):
BOM It is given that walking track is 500 m and Miss Hussain
OBC
Syndicate takes only one round. The given information is as follows-
8. (b) (i) Miss Yadav overtakes Miss Hussain twice and both

9. (e) are running in the clockwise direction, so Miss Yadav
10. (c) must have walked three times on the same track.
(ii) Miss Toppo crosses Miss Hussain three times and
11. (e)
12. (d) both are running in the same direction, so Miss
Toppo must have walked four times on the same
Solution for (13 – 20): track.

A (+) (H's son) (iii) Miss Sharma crosses Miss Hussain three times, so
(–) F (–) (D's wife and she must have walked three times on the same track,
H H's mother)
as both are running in the opposite directions.
E (+) (A's brother) Hence from this we can conclude that the distance
(+) covered are as follows:
D
B (+) (D's son) Miss Hussain- 500m
(–)
G
(E's sister) C Miss Yadav- 1500m
(–) (Wife of D's son)
Miss Toppo- 2000m
13. (d) Miss Sharma- 1500m
14. (b); H is the mother of G 26. (a) From the above result Total distance covered by
15. (b) Miss Sharma and Miss Toppo = 1500 + 2000 =
16. (e) 3500 m.
17. (a) 27. (d) From the above result as Miss Yadav and Miss
18. (c); A is the son of H and H is daughter of D. So A is Sharma both covered 1500 meter, but in opposite
grandson of D. directions, so both will meet five times on the track.
19. (a); B is the male while the rest are females 28. (c) From the above result Miss Toppo and Miss Yadav
20. (c) covered 2000 meter and 1500 meter respectively in
the same direction. So, Miss Toppo will overtake
Solution for (21 to 25):
twice Miss Yadav.
A (Finance)
Solution for (29–33):
st
D (CS) F (MCA) Lets denote these 12 students by their 1 letter of name,
like Abhishek is A and so on.
From the given information we can conclude that (C)
and (D) are at seat number 7 and 6 respectively. And
E (MBA) H (M.TECH)
(K) is the only person between (C) and (J) while (A) is
opposite to (K) . Hence, (A) , (K) and (J) must be at seat
number 5, 8 and 9 respectively.
B (B.com) C (B.TECH)
Then we have following two cases:
G (CA)