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TURUNAN FUNGSI ALJABAR

            39.     = −1
                               2
                  → −1 = −   + 3   + 9
                       2
                  →    − 3   − 10 = 0
                  → (   − 5)(   + 2) = 0 →    = 5 ,    = −2
                  ∴    = −2  → (−2, −1)
                  ∴    = 5 → (5, −1)

                                            ′
                          2
                     = −   + 3   + 9    →    = −2   + 3

                  PGS1, melalui titik singgung (-2, -1)
                  →    (−2) = −2. −2 + 3 = 7
                  ∴    −    =   (   −    )
                          1
                                      1
                   →    − (−1) = 7(   − (−2))
                  →    + 1 = 7(   + 2)
                  →    =  7   + 13

                  PGS2, melalui titik singgung (5, -1)
                  →   (5) = −2.5 + 3 = −7
                  ∴    −    =   (   −    )
                          1
                                      1
                  →    − (−1) = −7(   − 5)
                  →    + 1 = −7(   − 5)
                  →    = −7   + 34

            40.  Garis singgung sejajar dengan garis K: 4   − 2   + 3 = 0 maka gradien garis singgung = gradien
                                    4
                  garis K = − = −      = 2.
                                   −2
                         2
                                             ′
                     = 3   −    − 4  →    =    = 6   − 1
                                                  1
                  ∴    = 2  → 2 = 6   − 1 →    =
                                                  2
                         1           1  2  1          15     1    15
                  ∴    = →    = 3. ( ) − − 4 = −         → ( , − ) {titik singgung}
                         2           2     2          4      2    4
                               15            1        15                        19
                  PGS :    − (− ) = 2 (   − ) →    +     = 2   − 1  →    = 2   −
                                4            2         4                         4

            41.  Garis singgung tegak lurus dengan garis L: 3   + 6   − 7 = 0 maka gradien garis singgung =
                       −1           −1    6
                                =      = = 2.
                                                −3 ⁄ 6  3
                                                ′
                            2
                     = −5   − 3   + 2 →    =    = −10   − 3
                                                       1
                  ∴    = 2 → 2 = −10   − 3 →    = −
                                                       2
                           1               1  2        1         9       1 9
                  ∴    = − →    = −5. (− ) − 3. (− ) + 2 =   → (− , ) {titik singgung}
                           2               2           2         4       2 4
                            9               1          9                        13
                  PGS:    − ( ) = 2 (   − (− )) →    − = 2   + 1  →    = 2   +
                            4               2          4                         4





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