Page 25 - TUTORIAL MATEMATIKA IPA SEMESTER 2
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TURUNAN FUNGSI ALJABAR

            26.
                                          6      u(x)

                                          4                                                     v(x)


                                                               3                 6

                                       ′
                    (  ) =   (  ).   (  ) ,    (5) = ⋯
                  Pertama-tama tentukan dahulu persamaan garis u(x) dan v(x).
                  ∴ ingat rumus menentukan persamaan garis jika titik potong dengan sumbu X dan sumbu Y
                  Diketahui :      +      =     
                  ∴   (  )
                                                                             ′
                  → 6   + 6  (  ) = 36  →    +   (  ) = 6 →   (  ) = 6 −    →    (  ) = −1
                  ∴   (  )
                                   4
                             (  ) =    , 0 ≤    < 3
                    (  ) = {       3
                                  4,    ≥ 3
                                                                     ′
                  Karena yang diminta pada x = 5 maka   (  ) = 4  →    (  ) = 0
                     ′
                                                ′
                              ′
                  ∴    (  ) =    (  )  (  ) +   (  )   (  )
                                                 ′
                               ′
                      ′
                  →    (5) =    (5)  (5) +   (5)   (5) = −1.4 + 1.0 = −4

            27.  ∴ ingat aturan rantai dan aturan perkalian
                                                           ′
                   ′
                     (3   + 2). 3 = 1. √   + 1 +        → 3   (3   + 2) = 1. √   + 1 +    
                                               2√  +1                               2√  +1
                  ∴ 11 = 3   + 2  → 9 = 3    →    = 3
                                                                            3
                     ′
                                                   ′
                                                                                       ′
                  3   (11) = √3 + 1 +    3    → 3   (11) = √4 +   3  = 2 + =    11  →    (11) =  11
                                       2√3+1                     2√4        4   4              12
                         ′
                   → 12   (11) = 12.  11  = 11
                                     12

                     
                                2
            28.  ( ) (  ) =   (   + 2),
                     
                        ′        ′           ′
                                   (  )  (  )−  (  )   (  )  ′  2
                  → ( ) (  ) =            2      =    (   + 2). 2  
                                     (  (  ))
                      ′
                        (1)  (1)−  (1)  ′(1)
                                          ′
                                             2
                  →                   =    (1 + 2). 2.1
                          (  (1)) 2
                     2.3−(−2).−1                       4            2
                                                             ′
                                               ′
                                    ′
                  →            = 2   (3)  → 2   (3) =   →    (3) =
                        (3) 2                          9            9

                            2
                                            ′
            29.    (  ) =    + 4   + 1  →    (  ) = 2   + 4
                      ′
                                       2
                  ∴    (  ) = √10 −   
                        ′
                                           ′
                                 ′
                                                             2
                                                                         2
                  (      ) (  ) =    (  (  )).    (  ) = √10 − (   + 4   + 1) . (2   + 4)
                        ′
                                          2
                                                      2
                  (      ) (0) = √10 − (0 + 4.0 + 1) . (2.0 + 4) = √9. 4 = 12



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