Page 54 - TUTORIAL MATEMATIKA IPA KELAS XI-2

INTEGRAL FUNGSI ALJABAR

53.

4 4 2
= 1 → = = 4 ; = → =
1 2 2 √
2 9
= ∫ 1 − = − 4√ | = ( − 4√ ) − (4 − 4√4) = →
4 √ 4 4
9 7
− 4√ + 4 = → − 4√ + = 0
4 4
2 9 7
(√ ) − 4√ − = 0 → √ + √ = 4 ; √ . =
1
2
2
1
4 4
7
2
2
( + √ ) = + + 2 √ . = 4 → + + 2. ( ) = 16 → + = 50 = 25
2
1
2
2
1
1
2
2
1
√ 1
4
4
2

54.

2
4 2 2 4 4
= ∫ (3 − (√ ) ) = ∫ (9 − ) = [9 − 2 2
| ] =

2
2
4 2 2 2
{(9.4 − ) − (9.2 − )} = 12 satuan volume
2 2

55.

2 2 2
4
2 2
= → ∫ ( ) = ∫ (√ ) → ∫ = ∫ 0 →

0
0
0
2 5 4 5 5 4 5
5
2
|
5 0 = 2 | 0 → 5 = 2 → = → =
2
2

‘LEARNING IS FUN’ 53