Page 58 - Modul BRSL
P. 58
KERUCUT TERPANCUNG
Volume kerucut terpancung:
= 1 ( ) − 2( )
1 2 1 2
= . − .
2
1
3 1 3 2
1 2 2
= . − .
3 1 1 2 2
1 2 2
= + − .
3
1 2 2 2
= + −
3
1 2 2 2
= + ( − ).
3
1 2 2 2
= + − .
3 −
1
2
= + + − .
3 −
1 2
= + +
3
1 2 2
= + +
3
1 2 2
= + +
3
1 2 2
= + +
3
1 2 2
Jadi didapat: = × + + Terbukti.
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