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a. Pemantulan pada Cermin Datar
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#149 <5C1; 21H1>71> C9C9; 141<18 H1>7 4925>CD; 41A9 @5A@?C?>71> Gambar 6.4
@5A@1>:1>71> 4D1 B9>1A @1>CD< Pembentukan bayangan pada
5>71> 31A1 H1>7 B1=1 21H1>71> 25>41 4D1 49=5>B9 41> C971 49=5>B9 cermin datar
41@1C C5A25>CD; ?<58 35A=9> 41C1A )A?B5B @5=25>CD;1> 21H1>71>>H1 B1=1
B5@5AC9 @141 25>41 C9C9; !1< H1>7 C5A@5>C9>7 141<18 41<1= B5C91@ @A?B5B
@5=25>CD;1> 21H1>71> 8D;D= @5=1>CD<1> B5<1<D 25A<1;D
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mata
pengamat B'
B

Gambar 6.5
benda bayangan
D Ukuran benda persis sama dengan
ukuran bayangan
A C
s s'
0
.>CD; 25>41 H1>7 2D;1> 25AD@1 C9C9; 1C1D 71A9B >41 1;1> =5>41@1C
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5>41 41> 21H1>71> 81>H1 25A2541 41<1= 81< 1A18 ;9A9 41> ;1>1>>H1
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492131 =5<1<D9 35A=9> @5>D<9B1> 8DAD6>H1 81ADB 4921<9;
5A41B1A;1> 21H1>71> 25>41 @141 35A=9> 41C1A 41@1C 49B9=@D<;1>
218F1 B961C 21H1>71> 25>41 H1>7 4925>CD; ?<58 35A=9> 41C1A 141<18
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K = 1 H 1
K D;DA1> B1=1 25B1A 45>71> D;DA1> 25>41
K C 5 7 1 ;
K :1A1; 25>41 C5A8141@ 35A=9> B1=1 45>71> :1A1; 21H1>71> C5A8141@ Gambar 6.6
Ketika bercermin, posisi kiri benda
35A=9> menjadi posisi kanan bayangan

Cahaya dan Optika 111