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/                    A                                                           sumber tegangan
                       A
               038  <C0B0= F0=6 38?8=307:0= 030;07      A 0B0C



              3.   Mengukur Kuat Arus                                                              lampu
                  +=BC: <4=6C:C@ :C0B 0@CA ;8AB@8: 30;0< AC0BC @0=6:080= ;8AB@8:
              386C=0:0= 0<?4@4<4B4@ 0B0C 0<<4B4@  &4=6C:C@0= 0@CA ;8AB@8: 30;0< AC0BC
              ?4=670=B0@ 30?0B 38;0:C:0= 34=60= 20@0 <4=67C1C=6:0= 0;0B C:C@ 0@CA
              ;8AB@8:  0<?4@4<4B4@  A420@0 A4@8  A4?4@B8 ?030  #.$#2
                   0@0 <4<1020 A:0;0 0<?4@4<4B4@ 030;07 A410608 14@8:CB

                                          A:0;0 F0=6 38BC=9C:
                       0A8; ?4=6C:C@0=                     L 10B0A C:C@     K
                                           A:0;0 <0:A8<C<



              Contoh 8.2
               8 ;01>@0B>@8C< A4:>;07  180A0=F0 386C=0:0= 0<?4@4<4B4@ C=BC: <4=6C:C@ :C0B 0@CA   amperemeter
              &030 AC0BC ?4=6C:C@0= 0@CA ;8AB@8: 3830?0B 30B0 A4?4@B8 38BC=9C::0= ?030 60<10@ 14@8:CB
              *4=BC:0= 70A8; ?4=6C:C@0= 0<?4@4<4B4@ B4@A41CB                      Gambar 8.3
               #7#$                                                               Mengukur kuat arus listrik
               =5>@<0A8 F0=6 38?4@>;47 30@8 60<10@ B4@A41CB  F08BC A:0;0
              F0=6 38BC=9C:        A:0;0 <0:A8<C<        10B0A C:C@0=    70
                                                              0              100


               0A8; ?4=6C:C@0=      L
                                                                       0,5 A
               038  70A8; ?4=6C:C@0==F0


                                                                                               voltmeter
              Contoh 8.3

               @058: 14@8:CB <4=C=9C::0= :C0B 0@CA F0=6 <4=60;8@ 30;0< AC0BC @0=6:080= B4@BCBC?
               I(A)                        4@30A0@:0= 6@058: B4@A41CB  B4=BC:0= 10=F0:=F0
                                          <C0B0= ;8AB@8: F0=6 <4=60;8@ 30;0< @0=6:080=
              4                           A4;0<0   A ?4@B0<0 30;0< A0BC0= 2>C;C<1       P  lampu  Q
                                                                                    arus
                                           #7#$                                    listrik
              2                           I    0@8 2     A0<?08  2      A 38?4@>;47
                                               2       K       A  0@CA ?030 A4;0=6 E0:BC 8=8  +  –
                                              14@B0<107 A420@0 ;8=40@  $8;08 @0B0 @0B0=F0
                                      t(s)
                    2    4    6               030;07 A410608 14@8:CB                    baterai

                                                                                       voltmeter
                  0 2  0 2                                                                V

                   C<;07 <C0B0==F0   /    2                 A
              I    0@8 2     A A0<?08 2     A  38?4@>;47  2      A K   A     A   @CA ?030 A4;0=6 E0:BC
                  8=8 B4B0?           C<;07 <C0B0==F0  /    2                 A           ×

                   038  9C<;07 <C0B0= F0=6 <4=60;8@ <4;0;C8 @0=6:080= A4;0<0   A 030;07  P  lampu  Q
                                                                                    arus
                  /    /  /                                                        listrik




                                                                                         +  –
              4.   Mengukur Beda Potensial
                                                                                        baterai
                  +=BC: <4=6C:C@ 14A0@ 1430 ?>B4=A80; 0B0C B460=60= 38 0=B0@0 C9C=6 C9C=6  Gambar 8.4
              ?4=670=B0@  386C=0:0= D>;B<4B4@ F0=6 38@0=6:08:0= A4?4@B8 ?030  #.$#2       Cara mengukur beda potensial.

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