Page 12 - Pharmaceutical Analytical Chemistry II - Pharm D Clinical- 07-PA202
P. 12

To obtain: E0Cd                  Cd(s)

Half-reaction: Cd2+ + 2e─

By measuring Ecell for the cell represented schematically as:

Pt, H2 (p = 1.00 atm)  H+ (1.00 M)  Cd2+ (1.00 M)  Cd
E0cell = ─ 0.403 V, accordingly, E0 Cd2+/Cd = ─ 0.403 V

What does the Sign of Standard
Electrode potential, E0 imply?

E0Ag+/Ag = + 0.799 V             E0Cd2+/Cd = ─ 0.403 V

When the half-cell of interest exhibits a positive potential relative
to SHE, i.e.

It will behave spontaneously as Cathode when the cell is

discharging,

The spontaneously reaction is REDUCTION

Ag+ + e─      Ag(s)

Acts as oxidizing agent, stronger oxidant than H+

Cell reaction: H2(g) + 2Ag+      2H+ + 2Ag(s)

SHE acts as Anode

When the half-cell of interest exhibits a negative potential relative
to SHE, i.e.
It will behave spontaneously as Anode when the cell is
discharging,

The spontaneously reaction is OXIDATION

Cd(s)         Cd2+ + 2e─

Acts as reducing agent, stronger reductant than H+

Cell reaction: Cd(s) + 2H+       Cd2+ + H2(g)

SHE acts as Cathode

                             11
   7   8   9   10   11   12   13   14   15   16   17