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                    -1 d                  4 -5                   2 -1            2c                1       
                                                          
                                 +                                                                        
                                   
                   
                                                                                    
                                                           = 
                                                                                                                 
                                                                    -4 3
                    -b 3
                                        -3 b                                       c           a +1
                                                                                                                 

                                                             4c + (-c)
                       3           d - 5                                             2 + (-1)(a + 1)
                                                                                                                              
                                                                                                                           
                                                     =
                  
                                                                                                                              
                                                             -8c + 3c
                   -b - 3 3 + b
                                                                                          -4+ 3(a + 1)                     

                                 3             d   −5                     c 3                      a -   2  1 -    
                                                                                                                   
                                                               =
                                                             
                                                                                                                      
                         
                                                                            5
                                                                                                       3
                           − b     −3          3   + b              − c              − 4       + a         + 3     









          19 November 2020                                                                                                            20
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