Page 171 - NUMINO TB_3A
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N Q
number line (page 3, Unit 1) quadrilateral (page 55, Unit 6)
A line, which numbers can be located and A closed figure with four sides and four
marked. angles.
123456 quarter hour (page 147, Unit 16)
O A quarter hour has 15 minutes.
obtuse angle (page 68, Unit 7)
R
An angle that is larger than a right angle and ray (page 53, Unit 6)
smaller than 2 right angles.
A part of a line, with one endpoint, that
obtuse triangle (page 68, Unit 7) extends without end in one direction.
A triangle with 1 obtuse angle. regroup (page 25, Unit 3)
P To rename a number by exchanging
pentagon (page 55, Unit 6) amounts of equal values.
A closed figure with five sides and five 34 ones = 3 tens 4 ones
angles.
right angle (page 56, Unit 6)
An angle that forms a square corner.
place value (page 4, Unit 1) right triangle (page 64, Unit 7)
The value of a digit in a number by its place. A triangle with 1 right angle.
P.M (page 154, Unit 16)
The time between noon and midnight.
product (page 80, Unit 9)
The answer of a multiplication problem.
20 3 = 60
product
160
N Q
number line (page 3, Unit 1) quadrilateral (page 55, Unit 6)
A line, which numbers can be located and A closed figure with four sides and four
marked. angles.
123456 quarter hour (page 147, Unit 16)
O A quarter hour has 15 minutes.
obtuse angle (page 68, Unit 7)
R
An angle that is larger than a right angle and ray (page 53, Unit 6)
smaller than 2 right angles.
A part of a line, with one endpoint, that
obtuse triangle (page 68, Unit 7) extends without end in one direction.
A triangle with 1 obtuse angle. regroup (page 25, Unit 3)
P To rename a number by exchanging
pentagon (page 55, Unit 6) amounts of equal values.
A closed figure with five sides and five 34 ones = 3 tens 4 ones
angles.
right angle (page 56, Unit 6)
An angle that forms a square corner.
place value (page 4, Unit 1) right triangle (page 64, Unit 7)
The value of a digit in a number by its place. A triangle with 1 right angle.
P.M (page 154, Unit 16)
The time between noon and midnight.
product (page 80, Unit 9)
The answer of a multiplication problem.
20 3 = 60
product
160
