Page 146 - NUMINO Challenge_D2
P. 146
Problem solving 3 Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

1 The amount of chocolate bars Eric ate: 1 Among the factors of the denominator, find
2 the additions where the sum of the factors is
equal to the numerator.
The amount of chocolate bars Eric's little
17 12 4 1 12 3 2 8 6 3
brother ate: (1 1 ) 1 1 11 86218432
2 12 2 12 24
17 12 4 1 12 3 2
Therefore, the amount of chocolate bars eaten 24 24 24 24 24 24 24

by the two brothers was 8638621
1 1 12 1 13 . 24 24 24 24 24 24 24
2 24 24 24 24

8432
24 24 24 24

2 Since 1 11 , 11 1 5 , and since 1 Therefore, when you use the smallest
2 12 12 2 12 3
17
5 1 , 5 1 1 . number of fractions to express 24 as the
12 2 12 3 12
sum of different unit fractions,
11
Therefore, when you express 12 as the sum of 17 1 1 1 1 1 1
24 2 6 24 2 8 12
three different unit fractions, 11 1 1 1 .
12 2 3 12
1 1 1
3 4 8 .

Creative Thinking p.30~p.31 4 Since eight people want to share seven bagels,

each person can eat 7 of the bagel. However,
8
1 Each Egyptian fraction is represented in
if the bagels are divided as shown below, then
numerical fraction as shown below.
one person will have to eat 7 , which is 7 of
11 8
29 1 1
18 8 piece of bagel, and this won't be fair.

1 1 1 9 2 1 12 2 .
2 9 18 18 18 18 18 3

2 Find four proper divisors of 24 that add up to 24. If you express 7 as an Egyptian fraction,
8
1 2
Since 12 24 , there must be 2 among the 7 1 1 1 . Therefore, each person can
8 2 4 8

eat 1 of the bagel, 1 of the bagel, and 1
2 4 8
proper divisors. Therefore,

2 4 6 12 2 4 6 12 of the bagel.
24 24 24 24 24
1

1 1 1 1 .
2 4 6 12

Answer Key
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