Page 165 - NUMINO Challenge_C2
P. 165
Answer
Key
2 A maximum of 240 students can ride in 6 buses; Creative Thinking p.126~p.127
therefore, the total number of students should 1 When the remainder of a number divided by 3
be greater than 240. Also, if no seat is left over
in the 7th bus, then a total number of 40 7 and 4 is 2, that number is (common multiple of 3
280 students can ride in the bus. and 4) 2 that can be 14, 26, 38, 50, 62, or 74
Therefore, the smallest possible number of 5th and so on. Also, that number is divisible by 100,
grade students is 241 and the greatest possible so it is a divisor of 100.
number is 280. Divisor of 100: 1, 2, 4, 5, 10, 20, 25, 50, and 100.
Therefore, the number is 50.
Type 14-2 Applications of Remainders p.124~p.125
2 When the remainders of a number divided by 3,
1 2, common multiple
4, and 5 are 2, 3, and 4, respectively, then that
2 10, 22, 34, 46, number is 1 less than the common multiple of 3,
4, and 5.
3 10, 70, 130, (Common multiple of 3, 4, and 5) 1 59, 119,
179, 239, 299, 359, 419, 479, 539, .
4 130 Therefore, the number that is closest to 500 is
479.
Problem solving
3 When Jason and Brian add their money to buy
1 The number is 2 less than the common multiple of
two bicycles, they will be 30 32 $62 short.
5 and 4. Since the least common multiple of 5 and The sum of Jason’s and Brian's money is equal to
4 is 20, the numbers are 18, 38, 58, 78, and 98. the price of one bicycle. Therefore, the bicycle
Therefore, the number of 2-digit numbers is 5. costs $62.
2 The numbers that satisfy conditions and 4 Dan spent $5 $4.6 $0.4 less than Ted
are (common multiple of 4 and 5) 3 that are everyday and saved $4.4 $0.8 $3.6 more than
23, 43, 63, 103, 123, . Among the numbers Ted. Therefore, the trip lasted $3.6 $0.4 9
that satisfy conditions and , the smallest days and they began their trip with $5 9
number that satisfies condition is 83. $0.8 $45.8.
NUMINO Challenge C2
Key
2 A maximum of 240 students can ride in 6 buses; Creative Thinking p.126~p.127
therefore, the total number of students should 1 When the remainder of a number divided by 3
be greater than 240. Also, if no seat is left over
in the 7th bus, then a total number of 40 7 and 4 is 2, that number is (common multiple of 3
280 students can ride in the bus. and 4) 2 that can be 14, 26, 38, 50, 62, or 74
Therefore, the smallest possible number of 5th and so on. Also, that number is divisible by 100,
grade students is 241 and the greatest possible so it is a divisor of 100.
number is 280. Divisor of 100: 1, 2, 4, 5, 10, 20, 25, 50, and 100.
Therefore, the number is 50.
Type 14-2 Applications of Remainders p.124~p.125
2 When the remainders of a number divided by 3,
1 2, common multiple
4, and 5 are 2, 3, and 4, respectively, then that
2 10, 22, 34, 46, number is 1 less than the common multiple of 3,
4, and 5.
3 10, 70, 130, (Common multiple of 3, 4, and 5) 1 59, 119,
179, 239, 299, 359, 419, 479, 539, .
4 130 Therefore, the number that is closest to 500 is
479.
Problem solving
3 When Jason and Brian add their money to buy
1 The number is 2 less than the common multiple of
two bicycles, they will be 30 32 $62 short.
5 and 4. Since the least common multiple of 5 and The sum of Jason’s and Brian's money is equal to
4 is 20, the numbers are 18, 38, 58, 78, and 98. the price of one bicycle. Therefore, the bicycle
Therefore, the number of 2-digit numbers is 5. costs $62.
2 The numbers that satisfy conditions and 4 Dan spent $5 $4.6 $0.4 less than Ted
are (common multiple of 4 and 5) 3 that are everyday and saved $4.4 $0.8 $3.6 more than
23, 43, 63, 103, 123, . Among the numbers Ted. Therefore, the trip lasted $3.6 $0.4 9
that satisfy conditions and , the smallest days and they began their trip with $5 9
number that satisfies condition is 83. $0.8 $45.8.
NUMINO Challenge C2
