Page 145 - NUMINO Challenge_D1

Answer
Key

2 4 Since the product of ABCD and 4 is a 4-digit

67 number, A can either be 1 or 2. However, the
number in the ones place of the result is A;
1 therefore, A 2 and D 8.
6
6 ABCD A 2, B 1, C 7, D 8
4
0
DCBA

Since 67 1, must be 3. Therefore,

2 and 0. Because 67 6 , the 3 Magic Square p.24~p.25

possible numbers for are 4 or 7.

When 4 : 2, 2, 7, and 8.

When 7 : 2, 4, 7, and 9. Example 15 15, 60 3 3, 60, 5
15, 2 9 4
34 37
753
67 2 2 7 8 or 67 2 4 7 9 618

201 201

268 469 Try It Again 18 18, 6, 7, 7, 5, 6
268 469
18 17
00 72 82

3 9. ( , ) can be (8, 2), (7, 3), or (6, 4). The sum 4, 6, 4, 6

of the remaining six numbers is 45 9 10 26. 18 18
72
26 9 ( )9. 72
45 63
However, 92 9 98. Therefore 63
45
should be 8.

15 17 17
36
47 82 82
46 64
98
2 53 35

100 100 Type 3-1 Different Types of Magic Squares p.26~p.27

The order of (1, 3, 4) and (5, 6, 7) can be changed 1 The sum of numbers from 1 to 8 is 36, therefore
respectively. the sum of numbers in the two straight lines is
also 36. Since the sums of the four numbers in
each straight line are equal, the sum in each
straight line is 36 2 18.

2 The sum of the two numbers on the inside and the
sum of the two numbers on the outside is 18 2
9 in each case.

NUMINO Challenge D1