Page 143 - NUMINO Challenge_B1
P. 143
Answer
Key
3 According to the condition , sum of the digits 2 Alphametics p.16~p.17
between 8 and 9 is 26. 8 9 26 43. The Example 1, 2 1 9, 8
difference between 43 and 45 is 2, so 2 is
placed outside the range between 8 and 9. To Example 1 0, 0 6, 8 7, 2
obtain the smallest digit, 2 comes first, 8 comes
second, and 9 comes last. According to Type 2-1 Alphametics (1) p.18~p.19
condition , the sum of the digits between 7
and 8 is 19, which is 26 7. So 7 is in the 8th box. 1 The product of AB A is AB, so A 1.
Fill in the rest of the blanks with the remaining 2 2 2 4 and 2 2 4, so B 2, C 4.
digits 1, 3, 4, 5, and 6, according to the
conditions and . The smallest 9-digit Problem solving
number is shown below.
1 If A 1, then B 1. A and B must be different
2 81 65 3479
digits, so A 1. If A is greater than 3, then the
4 16
product would have 4 digits, so A cannot be
79
greater than 3. Therefore, A 2 and B 4, or
52 34
A 3 and B 9.
2 In B B, B must be 2 or 8 for the digit in the
ones place to be 4.
If B 2, then A 2 or 7. But 72
A cannot be the same as B, so 27
A 7. But if these values are 50 4
used, 4's are put into the 144
boxes, so B 2. 194 4
When B 8, A must be 3 or 38
8. But A cannot be the same as 83
B, so A 3. In this case, 4 is not 114
used in . 304
Therefore, A B 3 8 24. 3154
NUMINO Challenge B1
Key
3 According to the condition , sum of the digits 2 Alphametics p.16~p.17
between 8 and 9 is 26. 8 9 26 43. The Example 1, 2 1 9, 8
difference between 43 and 45 is 2, so 2 is
placed outside the range between 8 and 9. To Example 1 0, 0 6, 8 7, 2
obtain the smallest digit, 2 comes first, 8 comes
second, and 9 comes last. According to Type 2-1 Alphametics (1) p.18~p.19
condition , the sum of the digits between 7
and 8 is 19, which is 26 7. So 7 is in the 8th box. 1 The product of AB A is AB, so A 1.
Fill in the rest of the blanks with the remaining 2 2 2 4 and 2 2 4, so B 2, C 4.
digits 1, 3, 4, 5, and 6, according to the
conditions and . The smallest 9-digit Problem solving
number is shown below.
1 If A 1, then B 1. A and B must be different
2 81 65 3479
digits, so A 1. If A is greater than 3, then the
4 16
product would have 4 digits, so A cannot be
79
greater than 3. Therefore, A 2 and B 4, or
52 34
A 3 and B 9.
2 In B B, B must be 2 or 8 for the digit in the
ones place to be 4.
If B 2, then A 2 or 7. But 72
A cannot be the same as B, so 27
A 7. But if these values are 50 4
used, 4's are put into the 144
boxes, so B 2. 194 4
When B 8, A must be 3 or 38
8. But A cannot be the same as 83
B, so A 3. In this case, 4 is not 114
used in . 304
Therefore, A B 3 8 24. 3154
NUMINO Challenge B1
