Page 163 - NUMINO Challenge_B1
P. 163
Answer 12 Intersecting Points and Sections p.102~p.103
Key
Example 0 13
3 The numbers of squares in the 1st, 2nd, 3rd, and 3 5
4th arrangements are 1, 3, 9, and 27, respectively. Try It Again
So the number of squares increases by a factor of
3. Therefore, there will be 27 3 81 squares in 6
the fifth arrangement.
4 The numbers of marbles in , , , and are
1, 5, 13, and 25, respectively. These values can
be expressed as (0 0) (1 1), (1 1) (2 2),
(2 2) (3 3), and (3 3) (4 4). So the nth
arrangement has (n 1) (n 1) n n marbles.
Therefore, there will be (6 6) (7 7) 85
marbles in the seventh arrangement.
Example 4 , 6, 7, 8
Type 12-1 Number of Intersecting Points p.104~p.105
1
2 34
5
2
6
3 2, 3, 4, 5, 6
NUMINO Challenge B1
Key
Example 0 13
3 The numbers of squares in the 1st, 2nd, 3rd, and 3 5
4th arrangements are 1, 3, 9, and 27, respectively. Try It Again
So the number of squares increases by a factor of
3. Therefore, there will be 27 3 81 squares in 6
the fifth arrangement.
4 The numbers of marbles in , , , and are
1, 5, 13, and 25, respectively. These values can
be expressed as (0 0) (1 1), (1 1) (2 2),
(2 2) (3 3), and (3 3) (4 4). So the nth
arrangement has (n 1) (n 1) n n marbles.
Therefore, there will be (6 6) (7 7) 85
marbles in the seventh arrangement.
Example 4 , 6, 7, 8
Type 12-1 Number of Intersecting Points p.104~p.105
1
2 34
5
2
6
3 2, 3, 4, 5, 6
NUMINO Challenge B1
