Page 48 - FISIKA MATEMATIKA I PERSAMAAN LINEAR DAN PENERAPAN DALAM RANGKAIAN LISTRIK

11 −3 0 1 30
[−3 6 −1] [ ] = [ 5 ]
2
0 −1 3 3 −25

Selanjutnya, kita akan menyelesaikan persamaan linear

diatas dengan menggunakan metode crammer

11 −3 0
6
| | = [−3 6 −1 ] = 11 | −1 −1 | – (-3) | −3 −1 | +
3
3
0
0 −1 3
3 6
0 | |
0 −1
= 11 (19) – ((-3)(-9)) + 0(0) = 209-27+0 = 160

30 −3 0
| | = [ 5 6 −1] = 30 | 6 −1 | – (-3) | 5 −1 | +
1
−25 −1 3 −1 3 −25 3
5 6
0 | |
−25 −1
= 30 (17) – ((-3)(-10)) + 0(145) = 480

11 30 0
| | = [−3 5 −1] = 11 | 5 −1 | – 30 | −3 −1 | +
2
0 −25 3 −25 3 0 3
−3 5
0 | |
0 −25
= 11 (-10) – 30(-9) + 0(75) = 160

11 −3 30
| | = [−3 6 5 ] = 11 | 6 5 | – (-3)
3
0 −1 −25 −1 −25
−3 5 −3 6
| | + 30 | |
0 −25 0 −1
= 11 (-145) – ((-3)(75)) + 30(3) = -1280

42