Page 34 - Dimensi Tiga XII (Nurul Hidayati)
P. 34
AP = ½ AC = 4√2
T
TP = AP AT − 2
2
4 ( −
2
12
= ) 2 2
=
−
32
144
=
112
D P C = 4√7
A 8 cm B
Jadi jarak T ke ABCD = 4√7 cm
37
