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KUNCI JAWABAN


                        Pilihan Ganda

                               1.  e                                       14. d
                               2.  e                                       15. c
                               3.  b                                       16. a
                               4.  c                                       17. c
                               5.  b                                       18. c
                               6.  d                                       19. b
                               7.  d                                       20. d
                               8.  e                                       21. c
                               9.  a                                       22. b
                               10. e                                       23. a
                               11. a                                       24. b
                               12. e                                       25. d
                               13. b


                        Essay

                           1.  Diketahui

                               Massa terlarut = 15 gram     Mr = 60             Ditanya : Titik beku larutan?
                               P = 250 gram                 kf air = 1,86

                               Penyelesaian

                                                                              °
                               ∆   =    ∙                            ∆   =    −   
                                             
                                   
                                                                               
                                                                         
                                                                                    
                                      15 1000                        1,86 = 0 −   
                               ∆   =     ∙      ∙ 1,86                              
                                   
                                      60 250
                                      1                                 = −1,86℃
                               ∆   =    ∙ 4 ∙ 1,86                      
                                   
                                      4
                               ∆   = 1,86
                                   

                           2.  Diketahui
                               Mr glukosa = 180             Mr urea = 60              Suhu urea = 27°C = 300°K

                               Volume glukosa = 800 mL      Volume urea = 300 mL  Ditanya : Titik beku larutan?
                               Massa glukosa = 5 gram       Massa urea = 0,6 gram







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