Page 10 - Practical-workbook-organic-3

Calculations: Solid reactants, Liquid reactants

and Theoretical yield

⸪ One mole of any substance = Molecular weight in grams

Amount of A Amount of B Amount of C (grams)
(grams) (ml) (Theoretical Yield)

1 mole → 10 g 1 mole → 20 g Calculation of theoretical yield:
1. Balance the chemical equation
0.001 mole → ? 0.002 mole → ?
in terms of moles.
⸫ (A) Amount = Amount = 0.04 g

0.01 g As B is liquid, 2. Determine the limiting reactant;
the reactant used up first.
◼ A is the limiting m (grams)

reactant which is ⸪ B density = ρ = ( ) 3. Number of moles of the
used up first. = 0.7 g/ml limiting reactant = Number of

m (g) 0.04 moles of the product.
⸫ ( ) = =
ρ (ml) 0.7 1 mole → 48 g

⸫ = . 0.001 mole → ?

⸫ (C) Amount (theoretical yield) =

0.048 g

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