Page 22 - KerangkaEModulHkIINewton
P. 22
Jawab :
∑ = m . a
400 − 520 = (40)(a)
−120
= = - 3 m/s (E).
2
40
2. Pembahasan nomor 2 latihan soal
Diketahui :
17 m = 400 kg
2
a = 2 m/s
g = 9,8 m/s 2
Ditanya : T…?
Jawab :
N – w = m . a
T – w = m . a
2
2
T – (400 kg . 9,8 m/s ) = 400 kg . 2 m/s
T – 3.920 N = 800 N
T = 800 N + 3.920 N
T = 4.270 N (A)
