Page 37 - MODUL IPA KELAS VII
P. 37
38
Kunci Jawaban
-5
2.3 Diketahui: V 1 = 10 m³
0
∆T = 110—10= 100 C
-6 0
ᵧ = 33 x 10 / C
A. Pertambahan Volume
∆V =V 1. ᵧ . ∆t
B. Volume akhir
0
-6 0
-5
= 10 m³x 33 x 10 / C x 100 C
V 2 =V 1 + ∆V
-8
= 3.3 x 10 m³
= 10 cm³+ 0,033 cm³
= 0.033 cm³
V 2 = 10,033 cm³
2.4 Diketahui:
V 1 = 50 m
3
0
∆T=70 C
–6 0
ᵧ= 900 x 10 / C
Jawab:
a . Pertambahan volume
∆V = V 1. ᵧ. ∆T
–6 0
3
0
∆V = 50 m x 900 x 10 / C x 70 C
∆V = 3,2 m³ b . Volume akhir
V 2 =V 1 + ∆V
3
V 2 = 50 m + 3,2 m³
V 2 = 53,2 m³
38
