Page 37 - Translasi Geometri

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′
➢ Posisi akhir lukisan stelah digeser ’ , ′
′
= +

′
= +

▪ Koordinat A setelah digeser (A’)

′
= 10 + 80 = 90
′(90, 40)
′
= 0 + 40 = 40

▪ Koordinat B setelah digeser (B’)

′
= 80 + 80 = 160
B’(160, 40)
′
= 0 + 40 = 40

▪ Koordinat C setelah digeser (C’)

′
= 80 + 80 = 160
C’(160, 90)
′
= 50 + 40 = 90

▪ Koordinat D setelah digeser (D’)

′
= 10 + 80 = 90
D’(90, 90)
′
= 50 + 40 = 90

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