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‫اﻟ ﺎرﺻ ‪ Ksp = 1 X 1021-‬واﻟ ﻠﺔ اﻟ ﻟ ﺔ ﻟﻪ )‪(97 g/mol‬‬      ‫)‪ (١٤‬إذا ﻋﻠ أن ﺣﺎﺻﻞ اﻹذا ﺔ ﻟ‬
                                                       ‫ﻋ درﺟﺔ ﺣ ارة ‪ 25 oC‬اﺣ‬
‫اﻟ ﺎرﺻ اﻟ ﻰ ﺗ وب ﻓﻰ ‪ 100 g‬ﻣ اﻟ ﺎء اﻟ ﻘﻰ ‪.‬‬  ‫ﻠﺔ‬

                                                                       ‫ﺍﻟﺤــﻞ‬

‫)‪ZnS(S) ⇌ Zn+2(aq) + S2- (aq‬‬

                 ‫= ‪X mol/L‬‬                                                   ‫‪‬‬
‫أﯾ ﻧﺎت ‪ S-2 , Zn+2‬ﻛﺎﻵﺗﻰ ‪[S-2] = X ، [Zn2+] = X :‬‬                       ‫‪‬ﺗ‬

‫]‪KSP = [Zn+2] [S-2‬‬

‫]‪1 × 10-21 = [X] [X‬‬
‫‪1 × 10-21 = [X]2‬‬
‫‪X = 3.16227 × 10-11 mol/L‬‬

                           ‫= ‪3.16227 X 1011- mol/L‬‬

                                                    ‫‪X‬‬               ‫‪X‬‬

‫‪3.067 X 10-10 g = 97 X 0.1 X 3.16227 X 1011-‬‬

‫)‪ (١٥‬ﻣ ﻗﺎﻋ ﺛ ﺎﺋﻰ اﻟﻬ رو ﺷ ﺢ اﻟ و ﺎن ﻓﻰ اﻟ ﺎء ‪ ،‬ﻓﺈذا ﺎﻧ ﺔ ‪ pH‬ﻟﻬ ا اﻟ ﺗ ﺎو ‪8‬‬

                                                                    ‫اﺳ ﺞ ﺔ ‪ Ksp‬ﻟﻪ ‪.‬‬

‫‪POH = 14 - PH‬‬                                                                       ‫ﺍﻟﺤــﻞ‬
‫‪POH = 14 – 8 = 6‬‬
‫]‪POH = - log [OH-‬‬                                                      ‫ﻧﻔ ض أن ﺻ ﻐﺔ اﻟ‬
‫]‪6 = - log [OH-‬‬
‫‪[OH-] = 10-6‬‬

                                                       ‫ﻫﻰ ‪Y(OH)2 :‬‬
                              ‫– ‪Y(OH)2 ⇌ Y2+ + 2OH‬‬

‫ﻣ ﻣﻌﺎدﻟﺔ اﻟ ﻔﺎﻋﻞ ﻧ أن ‪ :‬ﺗ ‪ = Y2+‬ﺗ ]‪5 X 107- M = [OH-‬‬

‫‪KSp = [Y+2][OH-]2 = [5 X 107-][10-6]2 = 50 X 1020-‬‬

‫‪١٩٧  ‬‬

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